MGT602 GDB 2 Solution 17 Jan 2012

Solution
In my opinion the first option is the best solution in prevailing economic conditions of a country, that they should reduce their size of business operations to control the cost of business operations.Five arguments:-

1. 1. To reduce the consequence of double figure inflation rate on their business.
2. 2. Tell the energy crises are over, because energy availability is crucial for entrepreneurs.
3. 3. Tell the improvement of poor law and order situation in the country.
4. 4. Tell the terrorism is eradicated from the country, people feel fear to visit the market’
5. 5. The political condition are not positive which leads to inconsistent government policies, because govt. has to change it polices as per changing political scenario of the country which affect the business.

Following are the challenges that could be faced by an entrepreneur if he chooses the third option?

1. 1. Location
2. 2. Market penetration
3. 3. Competitors
4. 4. Brand
5. 5. Currency shifting
6. 6. Environment
7. 7. Law and regulation for foreigner investors
8. 8. Consumer
9. 9. Customer
10. 10. Quality
11. 11. Logistics’ supports
12. 12. Language
13. 13. Cultural difference
14. 14. Neighbor country relation with native country
15. 15. Masses response towards the products
16. demand & supply

Mth302 Assignment No:2 Fall 2011 solutions

Assignment # 2
MTH302 (Fall 2011)
Question No. 1:
Using the following data: 51, 13, 46, 49, 15, 16, 19, 18, 13, 48, 25, 36, 45, 52, 25, 50, 14, 36, 21,
45, 32, 40, 23, 21, 11, 25, 16, 18, 34, 32.
Solution:
1) Range = Max Value – Min Value
= 52 – 11
= 41
2) 7 Classes Frequency Distribution
First we found Class Width
Class Width = Range / Number of Classes
Number of Classes already given = 7
Now put in formula
= 41 / 7
= 5.85
= Round up 5.85 to 6
= 6
3) Relative Frequency (Column 3)
4) Percentage relative frequency (Column 4)
Tabulating Numerical Data
Frequency Distribution
Data in Ordered Array
11, 13, 13, 14, 15, 16, 16, 18, 18,19, 21, 21, 23, 25, 25, 25, 32, 32, 34, 36, 36, 40,45, 45, 46, 48, 49,50, 51, 52

Class Frequency Relative Frequency
= Frequency of the
Class Interval / Total
Frequency
%age Relative Frequency
= Frequency of the Class
Interval / Total Frequency
11 – 16 7 7/30=0.233 23
17 – 22 5 5/30=0.167 17
23 – 28 4 4/30=0.133 13
29 – 34 3 3/30=0.10 10
35 – 40 3 3/30=0.10 10
41 – 46 3 3/30=0.10 10
47 – 52 5 5/30=0.167 17
TOTAL: 30 1 100
5) The Mean
= (Sum of Total Value) / (Number of Total Values)
= 889 / 30
= 29.63